jQuery Form - 如何處理提交按鈕的點(diǎn)擊事件...
我們想知道如何處理提交按鈕的點(diǎn)擊事件。...
<!DOCTYPE html>
<html>
<head>
<script type='text/javascript'
src='http://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js'></script>
<style type='text/css'>
#addDest, #input2 {
display: none;
}
</style>
<script type='text/javascript'>
$(window).load(function(){
$('#a2').click(function() {
$('#addDest').show();
});
$('#addDest').click(function() {
if ($("#input2").is(':visible')) {
console.log("test");
};
$('#input2').show();
});
});
</script>
</head>
<body>
<button id="a2">A2</button>
<button id="addDest">Add</button>
<input type="text" id='input2'>
</body>
</html>
The code above is rendered as follows:
【input】
